For the ground-level harmonic oscillator wave function given by ?(x)=Cexp(?mk??x22?), |?|^2 has a maximum at x=0.
a. Compute the ratio of |?|^2 at x=+A to |?|^2 at x=0, where A is given by 12/k?A^2=(n+1/2)?? with n=0 for the ground level.
b. Compute the ratio of |?|2 at x=+2A to |?|^2 at x=0.
The ground state wave function is
where
where c is the normalization constant
The turning point is given the point where the energy is equal to the potential energy
Hence the positive turning point is
a) Therefore the wave function at x = 0 is
and hence
Wavefunction at the turning point is
Therefore
Hence the ratio is
b) Note that
And hence
Therefore the ratio is
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