Question

A simple U-tube contains honey. When water is poured into the left arm of the tube it makes the honey in the right arm rise 2.82 cm above its initial height. What is the height of the water sitting on the honey in the left arm? P_honey = 1.42 g/cm³. P_water = 1.00 g/cm³

Answer 1

Since, pressure is constant at every point in fluid.

then, pressure below water level = pressure below 2.82 cm height honey

_water*g*h_water = _honey*g*h_honey

h_water = (_honey/_water)*h_honey

given,

_water = 1.00 g/cm^3

_honey = 1.42 g/cm^3

h_honey = 2.82 cm

then, h_water = (1.42/1.00)*2.82 = 4.0044 cm = 4.00*10^-2 m

In two significant figure:

h_water = 4.00 cm

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