A thin convex lens is used to form a real image of an object placed between the focal point and
the lens. The object is moved closer to the lens. The new image:
Is closer to the lens and larger.
Is farther away from the lens and smaller.
Is closer to the lens and smaller.
Is farther away from the lens and lager.
More information is needed to work out the answer.
First of all we cannot obtain a real image when we place the object between focus and lens. The image formed will always be virtual.
Ignoring the typing error.
Let the image be virtual. Now as we can see in the ray diagrams when the object is moved closer to the lens we can clearly see that the image formed is closer to the lens and smaller in size as compared to the previous image. Hence that is our answer but it will not be possible to determine the exact location of the image until numerical data is provided. So we conclude that as per question our approach is theoretical hence answer is the image will be smaller and closer to the lens.
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