Question

A diverging lens with a focal length of -15 cm and a converging lens with a focal length of 15 cm have a common central axis. Their separation is 12 cm. An object of height 1.0 cm is 10 cm in front of the diverging lens, on the common central axis.

(a) Where does the lens combination produce the final image of
the object (the one produced by the second, converging lens)?

in cm

(b) What is the height of that image?

in cm

(c) Is the image real or virtual?

virtua

lreal

cannot tell from the given information

(d) Does the image have the same orientation as the object or is it inverted?

inverted

not inverted (erect)

cannot tell from the given information

Answer #1

hI

So, two lenses, one divergent and the other convergent. The object for the convergent lens is the image of the divergent one.

First obtain image of divergent lens:

Now this image will be the object for the convergent lens:

\

b) Same idea as before

for the divergent lens:

which means not inverted and shorter than object.

For the convergent lens, this will be the height of the object:

From the signs then we conclude that this final image is real, not inverted, and shorter than original one.

A diverging lens with a focal length of -19.7 cm and a
converging lens with a focal length of 11.0 cm have a
common central axis. Their separation is 39.5 cm. An
object of height 1.1 cm is 26.4 cm in front of
the diverging lens, on the common central axis. Find the location
of the final image produced by the combination of the two
lenses.
Where is the image located as measured from the converging
lens?
What is the...

A diverging lens with a focal length of -11.3 cm and a
converging lens with a focal length of 14.6 cm have a common
central axis. Their separation is 30.9 cm. An object of height 1.0
cm is 33.1 cm in front of the diverging lens, on the common central
axis. Find the location of the final image produced by the
combination of the two lenses.
Where is the image located as measured from the converging
lens?
What is the...

A converging lens with a focal length of 20 cm and a diverging
lens with a focal length of -34 cm are 74.0 cm apart. A 2.6-cm-tall
object is 40 cm in front of the converging lens.
1. Calculate the distance between image and diverging lens.
2. Calculate the image height.

A converging lens with focal length of 30 cm and a diverging
lens with focal length of 10 cm are 15 cm apart. A 4-cm-tall object
is 10 cm in front of the 30-cm-focal-length lens. Use ray tracing
to find the height of the image in cm

A converging lens and a diverging lens, separated by a distance
of 30.0 cm, are used in combination. The converging lens has a
focal length of 15.2 cm. The diverging lens is of unknown focal
length. An object is placed 19.3 cm in front of the converging
lens; the final image is virtual and is formed 12.0 cm in front of
the diverging lens. What is the focal length of the diverging
lens?

A converging lens with a focal length of +30 cm is placed 40 cm
to the left of a diverging lens with a focal length of -40 cm. An
object is placed 60 cm to the left of the converging lens. What is
the location and orientation of the image produced by the
combination of lenses?
Why is the answer B?
(a) Upright, on the right of the diverging lens and larger than
the main object
(b) Inverted, on the...

An object is placed 78.1 cm in front of a diverging lens with a
focal length of magnitude 37.3 cm. A converging lens having a focal
length of magnitude 27.49 cm is placed 105.3 cm past the first
lens. Where is the final image formed. Is this image Real or
Virtual. Inverted or Non-Inverted? Also calculate the
magnification.

A converging lens with a focal length of 60 cm and a diverging
lens with a focal length of -70 cm are 310 cm apart. A 2.7-cm-tall
object is 80 cm in front of the converging lens.
Calculate the distance between the final image and the diverging
lens.
Express your answer to two significant figures and include the
appropriate units.
Calculate the image height.
Express your answer to two significant figures and include the
appropriate units.

A converging lens with a focal length of 4.8 cm is
located 24.8 cm to the left of a diverging lens having a
focal length of -15.0 cm. If an object is located 9.8
cm to the left of the converging lens, locate and describe
completely the final image formed by the diverging lens.
Where is the image located as measured from the diverging
lens?
What is the magnification?
Also determine, with respect to the original object whether the
image...

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 36 minutes ago

asked 44 minutes ago

asked 51 minutes ago

asked 53 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago