Question

0.3kg of oil is taken from refreigitor at 4oC and added an alumunim pan of mass 1.5 kg at 25 oC. Find the time it takes to heat the oil and the pan at 300oc using 800 W stove.

Answer 1

Heat absorbed by 0.3 kg Oil to reach 300°C

from 4°C temperature is

H₁ = mC_oil ( ​​​​​​t_f -t_oil )

=0.3 × 1800 × ( 300 - 4) J

= 159840.0 J

Heat absorbed by aluminum pan

H₂ = m₂C_aluminum ( t_f - t_aluminium )

= 1.5 × 921×( 300 -25 ) J

= 379912.5 J

Total heat supplied

H = H₁ + H₂

= 539752.5 J

If t s is the time taken to reach at 300° C

Then P×t = H

Or, t = H/P

Or, t = 539752.5/800 S

= 674.7 S

### please provide specific heat capacity of the oil used to get accurate result.