A 4.22 cm tall object is placed 6.80 cm in front of a convex mirror with focal length -2.65 cm.
How big does the image appear?
(include minus sign if inverted)
A beam of light strikes a surface at 22 degrees from vertical. The beam proceeds through the new material at 49 degrees from vertical.
If the index of the original material is 1.50, what is the index of the new material?
Part - A
When the Object is lieing between infinity and pole of the mirror, the image is obatined between Pole and focus behind the mirror. The obtained image is Virtual, Upright and Dimished.
From Snells law we know n1Sin1 = n2Sin2
n1 = 1.5, 1=22 , 2=49
Substituting in the equation we get
1.5 Sin22 = n2 sin49
n2 = (1.5 * sin22)/ sin 49 = 0.74452
The refractive index of the new medium is 0.74452.
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