Question

A sphere with mass m = 10kg and R =0.5m begins at rest and accelerates uniformly...

A sphere with mass m = 10kg and R =0.5m begins at rest and accelerates uniformly for t = 20s to a final angular speed of w = 40rev/sec. it rotates about an axis through its center
a. what is the angular acc of sphere at t=20s
b angular acc of sphere at t = 10s
c. angular displacement at t = 20s
d. moment of inertia of the sphere
e. change in rotational energy from 0 to 20s
f. tangential component of the acc at a point R/2 from the axis of rotation at t = 10s
g. radial component of the acc at point R/2 from axis of rotation when sphere has accelerated half its final angular speed
h. final speed of the equator at t=20s
total distance at a point at the equator travels during 20s

Homework Answers

Answer #1

wf = wi + alpha t

wf = 40 x 2pi rad /s = 251.3 rad/s

251.3 = 0 + 20 alpha

alpha = 12.5 rad/s^2 .....Ans


(B) alpha is constant throughout.

alpha = 12.5 rad/s^2

(C) theta = wi t + alpha t^2 / 2

theta = 0 + (12.5)(20^2)/2

= 2513 rad

(D) I = 2 M R^2 / 5 = 1 kg m^2


(E) change in KE = I w^2 /2 = (1)(251.3^2)/2

= 3.16 x 10^4 J

(F) a_t = alpha r = (12.6) (0.5/2)

a_t = 3.15 m/s^2


(G) a_r = w^2 r = (20 x 2 pi )^2 (0.5/2)

a_r = 3950 m/s^2


(h) w = 251.3 rad/s

d = theta * r = 1256 m

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A disk with mass m = 8.5 kg and radius R = 0.35 m begins at...
A disk with mass m = 8.5 kg and radius R = 0.35 m begins at rest and accelerates uniformly for t = 18.9 s, to a final angular speed of ? = 29 rad/s. a) What is the angular acceleration of the disk? b) What is the angular displacement over the 18.9 s? c) What is the moment of inertia of the disk? d) What is the change in rotational energy of the disk? e) What is the tangential...
A disk with mass m = 9.5 kg and radius R = 0.3 m begins at...
A disk with mass m = 9.5 kg and radius R = 0.3 m begins at rest and accelerates uniformly for t = 18 s, to a final angular speed of ω = 28 rad/s. A)What is the angular acceleration of the disk? B)What is the angular displacement over the 18 s? C)What is the moment of inertia of the disk? D)What is the change in rotational energy of the disk? E)What is the tangential component of the acceleration of...
A disk with mass m = 10.3 kg and radius R = 0.34 m begins at...
A disk with mass m = 10.3 kg and radius R = 0.34 m begins at rest and accelerates uniformly for t = 16.8 s, to a final angular speed of ω = 26 rad/s. 1) What is the angular acceleration of the disk? rad/s2 2) What is the angular displacement over the 16.8 s? rad 3) What is the moment of inertia of the disk? kg-m2 4) What is the change in rotational energy of the disk? J 5)...
An object rotates about a fixed axis, and the angular position of a reference line on...
An object rotates about a fixed axis, and the angular position of a reference line on the object is given by ? = 0.240e8t, where ? is in radians and t is in seconds. Consider a point on the object that is 5.00 cm from the axis of rotation. At t = 0, what are the magnitudes of the point's (a) tangential component of acceleration and (b) radial component of acceleration?
An ultracentrifuge accelerates from rest to 9.91×105 rpm9.91×105 rpm in 1.99 min1.99 min. What is its...
An ultracentrifuge accelerates from rest to 9.91×105 rpm9.91×105 rpm in 1.99 min1.99 min. What is its angular acceleration in radians per second squared? angular acceleration: rad/s2rad/s2 What is the tangential acceleration of a point 9.70 cm9.70 cm from the axis of rotation? tangential acceleration: m/s2m/s2 What is the radial acceleration in meters per second squared and in multiples of gg of this point at full revolutions per minute? radial acceleration: m/s2m/s2 radial acceleration in multiples of gg:
An ultracentrifuge accelerates from rest to 9.95×105 rpm9.95×105 rpm in 1.63 min1.63 min. What is its...
An ultracentrifuge accelerates from rest to 9.95×105 rpm9.95×105 rpm in 1.63 min1.63 min. What is its angular acceleration in radians per second squared? angular acceleration: rad/s2rad/s2 What is the tangential acceleration of a point 9.70 cm9.70 cm from the axis of rotation? tangential acceleration: m/s2m/s2 What is the radial acceleration in meters per second squared and in multiples of ?g of this point at full revolutions per minute? radial acceleration: m/s2m/s2 radial acceleration in multiples of ?g:
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.80 min. (a) What is its angular...
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.80 min. (a) What is its angular acceleration in rad/s2? rad/s2 (b) What is the tangential acceleration, in m/s2, of a point 11.80 cm from the axis of rotation? m/s2 (c) What is the radial acceleration, in m/s2, of this point at full rpm? m/s2 (d) Express this radial acceleration as a multiple of g. g
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.50 min. (a) What is its angular...
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.50 min. (a) What is its angular acceleration in rad/s2? __________ rad/s^2 (b) What is the tangential acceleration, in m/s2, of a point 10.80 cm from the axis of rotation? _________ m/s2 (c) What is the radial acceleration, in m/s2, of this point at full rpm? __________ m/s2 (d) Express this radial acceleration as a multiple of g. _________ g
A sphere of mass M, radius r, and rotational inertia I is released from rest at...
A sphere of mass M, radius r, and rotational inertia I is released from rest at the top of an inclined plane of height h as shown above. (diagram not shown) If the plane has friction so that the sphere rolls without slipping, what is the speed vcm of the center of mass at the bottom of the incline?
A merry-go-round starts from rest and accelerates uniformly over 19.5 s to a final angular velocity...
A merry-go-round starts from rest and accelerates uniformly over 19.5 s to a final angular velocity of 6.25 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 4.00 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (d) Find the person's tangential acceleration.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT