Question

2) A dentist's drill starts from rest. After 3.30 s of constant angular acceleration it turns...

2) A dentist's drill starts from rest. After 3.30 s of constant angular acceleration it turns at a rate of 2.40 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (10 points) (b) Determine the angle (in radians) through which the drill rotates during this period. (10 points)

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Answer #1

Angular acceleration is 761.2 rad/s

During the given time period drill rotate through 6.28 rad

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