Question

A uniform 33.0-kg beam of length ℓ = 5.70 m is supported by a vertical rope located d = 1.20 m from its left end as in the figure below. The right end of the beam is supported by a vertical column.

a) Find the tension in the rope.

(b) Find the force that the column exerts on the right end of the beam. (Enter the magnitude.

Answer 1

A)

we'll say that the center of gravity is halfway along the block, or at radius L/2, and that W will be the magnitude of the weight force, mg.

So, Στ=0=F*0+T*(L-d)-W(L/2)

weight force is subtracted because it's in downward direction.

Thus, T*(L-d)-W(L/2)=0

T*(L-d)=W*L/2

T=W*L/(2(L-d))

then
T = m g L / [2(L - d)]
T = 33.0*9.8*5.70 / [2(5.70 - 1.20)] = 204.8 N

B)

sum of all forces=0, so T+F-W=0

F = W-T
F = mg - T = 33.0*9.8-204.8 = 118.6 N

Hope this helps you!

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