Modern roller coasters have vertical loops like the one shown in the figure. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. |
A) What is the speed of the roller coaster in m/s at the top of the loop if the radius of curvature there is 11 m and the downward acceleration of the car is 1.7g? Note that g here is the acceleration due to gravity.
B) The beginning of this roller coaster is at the top of a high hill. If it started from rest at the top of this hill, how high, in meters, above the top of the loop is this initial starting point? You may assume there is no friction anywhere on the track.
C) If it actually starts 7.5 m higher than your answer to the previous part (yet still reaches the top of the loop with the same velocity), how much energy, in joules, did it lose to friction? Its mass is 1900 kg.
Sorry there was a calculation error.
Now if your query is been resolved please upvote and if you have any doubt please comment down below,I'll be happy to help you out. It takes a lot of time and hardwork to answer each question please encourage the effort by upvote/like to answer. Thanks and regards.
Get Answers For Free
Most questions answered within 1 hours.