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A single force acts on a 3.7 kg particle-like object in such a way that the...

A single force acts on a 3.7 kg particle-like object in such a way that the position of the object as a function of time is given by x = 2.1t - 1.5t2 + 4.2t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 7.2 s.

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Answer #1

The position as a function of time is

That gives us

And the acceleration is

So, the force as a function of time is

Now, the work done by the force is

So, the work done by the force is 7.78 x 10^5 J.

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