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qt9.2 A stone is dropped at t = 0. A second stone, with 5 times the...

qt9.2

A stone is dropped at t = 0. A second stone, with 5 times the mass of the first, is dropped from the same point at t = 170 ms. (a) How far below the release point is the center of mass of the two stones at t = 430 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time?

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Answer #1

in order to find the distance of center of mass and speed of center of mass we have to find the distance travelled by both mase at time t =430 ms.then the centre of mass

y =(m1y1+m2y2)/(m1+m2)

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