At the bow of a ship on a stormy sea, a crewman conducts an experiment by standing on a bathroom scale. In calm waters, the scale reads 178 lblb . During the storm, the crewman finds a maximum reading of 225 lblb and a minimum reading of 133 lblb .
Find the magnitude of the maximum upward acceleration experienced by the crewman.
Find the magnitude of the maximum downward acceleration experienced by the crewman.
Given,
The weight in calm water, W = 178 lb
The maximum weight, W max = 225 lb
The minimum weight, Wmin = 133 lb
a)
The maximum upward acceleration is,
By using force balance on crewman in vertical direction,
F = (Wmax - W)
m a = (Wmax - W)
a = (Wmax - W) / m
where, is the mass of a crewman, m = W /g
a = (Wmax - W) * g / W
a = (225 - 178) * 9.8 / 178
a = 2.59 m/s2
b)
The maximum downward acceleration is
F = Wmin - W
- m a = Wmin - W
a = (W - Wmin ) / m
a = ( W - Wmin ) * g / W
= (178 - 133) * 9.8 / 178
= 2.48 m/s2
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