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A ball is thrown with an initial velocity of 43.8 m/s. How long does it take...

A ball is thrown with an initial velocity of 43.8 m/s. How long does it take for the ball to stop in seconds?

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Answer #1

Initial velocity Vi = 43.8 m/s and for the ball to stop final velocity should be Vf = 0 m/s.

Since there is no mention of any acceleration we can consider the ball is moving under gravitational acceleration and falls freely after throwing.

The kinematic equation of an object under free fall is

Where g = 9.8 m/s2 is the gravitational acceleration and t is the time.

now substituting the values of Vi, Vf, and g we get

  

  

Therefore it takes 4.47 sec for the ball to stop.

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