Question

A car traveling at 17.2 m/s skids to a stop in 188 m from the point...

A car traveling at 17.2 m/s skids to a stop in 188 m from the point where the brakes were applied.

In what distance would the car have stopped had it been going 58.5 m/s , if tires and road condition were unchanged (i.e. if the acceleration were the same)?

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Answer #1

Initial speed of the car = V1 = 17.2 m/s

Final speed of the car = V2 = 0 m/s (Comes to a stop)

Distance the car travels before stopping = D1 = 188 m

Acceleration of the car = a

V22 = V12 + 2aD1

(0)2 = (17.2)2 + 2a(188)

a = -0.7868 m/s2

New initial speed of the car = V3 = 58.5 m/s

New final speed of the car = V4 = 0 m/s

New distance the car travels before stopping = D2

All the conditions are same therefore the acceleration of the car is the same.

V42 = V32 + 2aD2

(0)2 = (58.5)2 + 2(-0.7868)D2

D2 = 2175 m

Stopping distance of the car if it is going at a speed of 58.5 m/s = 2175 m/s

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