Question

Speed means the absolute value of the velocity, hence it is always non-negative. While the sign...

Speed means the absolute value of the velocity, hence it is always non-negative. While the sign of the velocity indicates the direction of the motion, the speed is insensitive to the direction. For example, speed is the value displayed by car’s speedometer; it does not indicate the direction of driving (e.g., northbound versus southbound). At time t = 0 seconds (s) an object has zero velocity and it starts a free fall from the altitude of 1200 metres (m) above Earth’s surface. We assume that the air resistance is negligible and the gravitational acceleration is −9.81 m/s 2 . At the time instant when the object is falling with the speed of 50 m/s, its brake engines are ignited and from then on, the object is moving vertically with a constant acceleration of 1 m/s 2 until it hits the ground. (Note the sign of the acceleration: the breaking force is stronger than the gravitational force.)

(a) Determine two position functions: yf (t) for the free fall motion and yb(T) for the motion with brakes ignited. The new time variable T is such that T = 0 is the time when the brakes are ignited.

(b) Determine the time when the object hits the ground and the speed at which it hits the ground. Express the hitting time in terms of t (total travel time)

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculating speed and constant velocity. A rock is released at t = 0.00 s from the...
Calculating speed and constant velocity. A rock is released at t = 0.00 s from the top of a tall building. Its speed at t = 1.18 s is A. 12.0 m/s B. 11.6 m/s C. 1.12 m/s D. 11.0 m/s Which of the following statements concerning a constant velocity motion is incorrect? A. The acceleration is a non-zero constant. B. The speed is constant. C. The direction of motion does not change. Which of the following statements concerning a...
A 3 kg cannonball is shot straight up from ground level at a velocity of 30...
A 3 kg cannonball is shot straight up from ground level at a velocity of 30 m/s. For the following questions, neglect air resistance and assume acceleration due to gravity is -10 m/s2. (a) Use the 1D equations of motion to find: i. The maximum height the cannonball reaches ii. The time it takes to reach this height iii. The time it takes to fall back to the ground iv. The speed with which it hits the ground
A baseball player standing 20.0m away from a flat-roof garage throws a ball with the speed...
A baseball player standing 20.0m away from a flat-roof garage throws a ball with the speed 16.0m/s at 40◦ above the horizontal. The ball leaves player’s hand 2.0m above the ground and lands on the roof a 4.0m above the ground. How far above the ground does the ball reach? How long is the ball in flight before landing on the roof? How far past the edge of the roof, show as x in the picture, does the ball land?...
When the velocity v of an object is very​ large, the magnitude of the force due...
When the velocity v of an object is very​ large, the magnitude of the force due to air resistance is proportional to v squared with the force acting in opposition to the motion of the object. A shell of mass 5 kg is shot upward from the ground with an initial velocity of 800 ​m/sec. If the magnitude of the force due to air resistance is ​(0.1​)v squared​, when will the shell reach its maximum height above the​ ground? What...
The graph gives the vertical velocity of the rocket versus time after it is launched at...
The graph gives the vertical velocity of the rocket versus time after it is launched at t = 0.0 s. The rocket starts climbing with a constant speed of 23 m/s. At t = 2.0 s the rocket engine shuts off and the rocket is then in free-fall motion and falls back to the ground. What maximum height above the ground does the rocket reach?
An object of mass 2kg is free falling being given an initial velocity of -10 m/s....
An object of mass 2kg is free falling being given an initial velocity of -10 m/s. its initial vertical position is 20 m. a.) sketch v(t), y(t), and a(t) graphs for the motion. b.) Find the time when the object reaches the ground. c.) Find the velocity of the object at the impact d.) Suppose that simultaneously another object is projected straight up with an initial velocity of 10 m/s. prove if the other project will pass the first.
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial...
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 81.0 m/s at ground level. The engines then fire, and the rocket accelerates upward at 3.90 m/s2 until it reaches an altitude of 1020 m. At that point its engines fail, and the rocket goes into free fall, with an acceleration of ?9.80 m/s2. (You will need to consider the motion while the engine is operating and the free-fall motion separately.) (a)...
1. While standing at the edge of a bridge, you throw a ball upward with an...
1. While standing at the edge of a bridge, you throw a ball upward with an initial speed of 12 m/s. The ball subsequently falls to the ground, which is 45 m below the point where the ball leaves your hand. (a) How much time is the ball in the air? (b) What is the velocity of the ball when it hits the ground? 2. An object is fired straight up at a speed of 12m/s. Calculate (a) its maximum...
An archer shoots an arrow with an initial speed of 45 m/s, at an angle of...
An archer shoots an arrow with an initial speed of 45 m/s, at an angle of 70° from the horizontal. How much time does it take to reach the top of its trajectory? 4.13 s What is its velocity (magnitude and direction) at the top of its trajectory?15.4m/s^2 What is its acceleration (magnitude and direction) at the top of its trajectory?9.8m/s^2 How high does it go?91.23m A)Assume that the arrow hits the ground 2 meters below the level from which...
1. Triple the net force on an object is : mass triples. acceleration triples. velocity triples....
1. Triple the net force on an object is : mass triples. acceleration triples. velocity triples. 2. As you walk along a level floor, the friction force acting on your feet points in what direction? In the direction of your motion Down Up Cannot decide from the given information Opposite to the direction of your motion speed triples. momentum triples. 3. Let m be your mass. When you are standing up, the normal force acting on you from the floor...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT