Question

M, a solid cylinder (M=1.47 kg, R=0.135 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.690 kg mass, i.e., F = 6.769 N. Calculate the angular acceleration of the cylinder. Tries 0/8 If instead of the force F an actual mass m = 0.690 kg is hung from the string, find the angular acceleration of the cylinder. Tries 0/8 How far does m travel downward between 0.690 s and 0.890 s after the motion begins? Tries 0/8 The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.571 m in a time of 0.550 s. Find Icm of the new cylinder. Tries 0/8

Answer 1