Question

The Lab experiment of a vibrating string was modified to be a 90-cm aluminum string joined to an 129.9
cm steel string. The vertical pulling mass was 10 kilograms over a pulley. The standing wave pattern had
4*Y loops in the aluminum section and n loops in the steel section. One loop represents half wavelength
etc in the Lab Book drawings. There were 4*Y + n loops. There were 4*Y + n + 1 nodes, counting the
end points. Y = 4, if zero Y = 2
Use density values of 2.6 g/cc for aluminum and 7.8 g/cc for steel, with a uniform cross section area 0.01
sq-cm,
Find the frequency of the vibrator and n.
Hint: mass per unit length = mass per unit volume * cross section area,
Hint: Kundt’s tube

Answer 1