A bullet is fired through a board 7.0 cm thick in such a way that the bullet's line of motion is perpendicular to the face of the board. The initial speed of the bullet is 510 m/s and it emerges from the other side of the board with a speed of 410 m/s. (a) Find the acceleration of the bullet as it passes through the board. m/s2 (b) Find the total time the bullet is in contact with the board. s
Initial speed of the bullet vi=510m/s
Final speed of the bullet vf=410m/s
Distance traveled by the bullet d=7cm=0.07m
(a)
Assuming the acceleration of the bullet is constant, the motion of the bullet as it passes through the board is governed by the kinematics equations for uniformly accelerating motion. To find the acceleration in terms of given quantities we use
(b)
To find time in terms on know quantities we use
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