Question

Gloop index: 2.217. Ethanol: 1.36 A beam of light travels through ethanol and then enters a piece of Mossious gloop. If the light is incident at an angle of 27 degrees, then what is the angle of refraction in the gloop?

Answer 1

Refractive index of the gloop, ng = 2.217
Refractive index of the ethanol, ne = 1.36
Angle of incidence, i = 27 degrees
Consider the angle of refraction as r

Using Snell's law,
ne * sini = ng * sinr
sinr = [ne * sini] / ng
r = sin^-1{[ne * sini] / ng}
= sin^-1{[1.36 * sin(27)] / 2.217}
= 16.17 degrees