Question

A merry-go-round with a moment of inertia equal to 1250kg?m2 and a radius of 2.5 m...

A merry-go-round with a moment of inertia equal to 1250kg?m2 and a radius of 2.5 m rotates with negligible friction at 1.70 rad/s. A child initially standing still next to the merry-go-round jumps onto the edge of the platform straight toward the axis of rotation, causing the platform to slow to 1.35 rad/s.What is her mass?

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Answer #1

Apply law of conservation of angular momentum.

         

Here, is the moment of inertia of the merry-go-round, is the initial angualar speed of the merry go round,

m is the mass of the child, r is the distance of the child from the axis of rotation, and is the final angular speed.

Rearrange the equation for mass of the child.

                  

Substitute all value in the above equation.

                  

                    

Therefore, the mass of the child is .

                         

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