Question

A uniform rod of mass 250 g and length 75 cm is free to rotate in...

A uniform rod of mass 250 g and length 75 cm is free to rotate in a horizontal plane around a fixed vertical axis through its center, perpendicular to its length. Two small beads, each of mass 25 g, are mounted in grooves along the rod. Initially, the two beads are held by catches on opposite sides of the rod’s center, 9 cm from the axis of rotation. With the beads in this position, the rod is rotating with an angular velocity of 7.5 rad/s. When the catches are released, the beads slide outward along the rod.

a) What is the rod’s angular velocity, in rad/s, when the beads reach the ends of the rod?

b) What is the rod’s angular velocity, in rad/s, if the beads fly off the rod?

Homework Answers

Answer #1

pls upvote

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A uniform rod of mass 190 g and length 100 cm is free to rotate in...
A uniform rod of mass 190 g and length 100 cm is free to rotate in a horizontal plane around a fixed vertical axis through its center, perpendicular to its length. Two small beads, each of mass 18 g, are mounted in grooves along the rod. Initially, the two beads are held by catches on opposite sides of the rod's center, 18 cm from the axis of rotation. With the beads in this position, the rod is rotating with an...
A uniform rod of mass 3.40×10−2 kg and length 0.410 m rotates in a horizontal plane...
A uniform rod of mass 3.40×10−2 kg and length 0.410 m rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.190 kg , are mounted so that they can slide along the rod. They are initially held by catches at positions a distance 5.50×10−2 m on each side from the center of the rod, and the system is rotating at an angular velocity 28.0 rev/min ....
A uniform rod of mass 3.45×10−2 kgkg and length 0.360 mm rotates in a horizontal plane...
A uniform rod of mass 3.45×10−2 kgkg and length 0.360 mm rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.250 kgkg , are mounted so that they can slide along the rod. They are initially held by catches at positions a distance 4.80×10−2 mm on each side from the center of the rod, and the system is rotating at an angular velocity 28.0 rev/minrev/min ....
A uniform, 0.0350 kg rod of length 0.450 m rotates in a horizontal plane about a...
A uniform, 0.0350 kg rod of length 0.450 m rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.0200 kg, are mounted so that they can slide without friction along the rod. They are initially held by catches at positions 0.0550 m on each side of the center of the rod, and the system is rotating at 48.0 rev/min. With no other changes in the system,...
A uniform wire of mass M and length d rotates in a horizontal plane about an...
A uniform wire of mass M and length d rotates in a horizontal plane about an axis passing through its center. Two small beads, each of mass m, are placed on the wire; friction between the beads and the wire is negligible. The beads are initially held on the wire by catches at a distance d/4 on either side of the center, and the system rotates with angular speed ω0. The catches are then released, and the beads slide outward...
A uniform thin rod of length 0.56 m and mass 3.2 kg can rotate in a...
A uniform thin rod of length 0.56 m and mass 3.2 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a 3.5 g bullet traveling in the rotation plane is fired into one end of the rod. As viewed from above, the bullet's path makes angle θ = 60° with the rod. If the bullet lodges in the rod and the angular velocity of the rod is 12.0 rad/s...
A thin uniform rod has a length of 0.490 m and is rotating in a circle...
A thin uniform rod has a length of 0.490 m and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary. The rod has an angular velocity of 0.37 rad/s and a moment of inertia about the axis of 3.50×10−3 kg⋅m2 . A bug initially standing on the rod at the axis of rotation decides to crawl out to the other end of...
A thin uniform rod has a length of 0.430 m and is rotating in a circle...
A thin uniform rod has a length of 0.430 m and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary. The rod has an angular velocity of 0.32 rad/s and a moment of inertia about the axis of 3.20×10−3 kg⋅m2 . A bug initially standing on the rod at the axis of rotation decides to crawl out to the other end of...
A long, uniform rod of length  0.510 mm and is rotating in a circle on a frictionless...
A long, uniform rod of length  0.510 mm and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary. The rod has an angular velocity of 0.4 rad/srad/s and a moment of inertia about the axis of 2.70×10−3 kg⋅m2kg⋅m2 . An insect initially standing on the rod at the axis of rotation decides to walk to the other end of the rod. When the...
A uniform rod of mass M and length L is pivoted at one end. The rod...
A uniform rod of mass M and length L is pivoted at one end. The rod is left to freely rotate under the influence of its own weight. Find its angular acceleration α when it makes an angle 30° with the vertical axis. Solve for M=1 Kg, L=1 m, take g=10 m s-2. Your answer in X.X rad s-2. Hint: Find the center of mass for the rod, and calculate the torque, then apply Newton as τ= Ι·α
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT