Question

The Hindenburg Zeppelin used 1.98 x 10⁵ m³ of hydrogen to lift itself plus any payload. The density of the hydrogen can vary due variations in the pressure of the gas plus about 10% due to temperature changes. On a particular day the density of air was 1.235 and the density hydrogen was 0.094. Considering only the volume of the hydrogen and an equal volume of air, what is the maximum weight that the Hindenburg could lift, (including its own weight)?

Answer 1

Given that the density of hydrogen = 0.094 kg/m3

density of air =1.235 kg/m3

The bouyant force due to the air = 1.235 X 1.98 X9.8X 105 N

Weight of the air ship = 0.094 X1.98 X105 X9.8 N

let the mass of load be m then weight of load = mg

for equilibrium

1.235 X 1.98 X9.8X 105 N = 0.094 X1.98 X105 X9.8 N +mg

m= (1.235-0.094)X1.98X 105 = 2.24 X 105 kg

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