Question

Maximum Height: H = 40 m. theta=90 degrees From this measured value of H, compute the...

Maximum Height: H = 40 m. theta=90 degrees

From this measured value of H, compute the initial speed v0 of the ball. Show your calculation. Initial Speed: v0 = _________________ m/s.

Homework Answers

Answer #1

theta = 90 degree .it means motion of ball is vertically to the ground so we apply motion formula

if you have any query please comment

please give positive rating

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A ball at is launched at 30 degrees above the horizontal with an initial speed at...
A ball at is launched at 30 degrees above the horizontal with an initial speed at t = 0 of v0 = 1.00 m/s, from an initial height h0 = 1.00 m above the ground. What is the maximum height hmax it achieves above the ground, and what is the time tmax it takes to get there? Show your final formulas, and the numerical results.
1. (4p) One object is dropped from a height h = 1.0202030304040505 m (initial velocity is...
1. (4p) One object is dropped from a height h = 1.0202030304040505 m (initial velocity is zero) and it hits the ground after a time t1. A second object is launched horizontally from the same height h = 1.0202030304040505 m (as shown in the figure below) with the horizontal velocity v0 = 1.0102030405 m/s, and it hits the ground after a time t2. Compute the time difference Δt = t2 – t1. (Neglect the air friction). Explain your answer. Show...
A ball is thrown at an angle of 40 degrees above the horizontal at a speed...
A ball is thrown at an angle of 40 degrees above the horizontal at a speed of 16.0 m/s from the top of a 12.4 m tall bldg. What is the maximum height of the ball above the ground?
Two Buildings A and B are each of height H as measured from the ground and...
Two Buildings A and B are each of height H as measured from the ground and are located a distance L apart as shown in the figure. A ball is shot horizontally with a velocity v0 ​from building A such that it just hits the middle of building B before hitting the ground. At what new velocity v' would the ball have to be shot from building A such that the ball now hits Building B one-quarter of the way...
A rubber ball of mass m is dropped from a height h. If the ball loses...
A rubber ball of mass m is dropped from a height h. If the ball loses energy on each bounce so that its speed just after each bounce is 90% of its speed just before each bounce, then Önd an expression for the height the ball reaches after the 3rd bounce
A ball is thrown toward a cliff of height h with a speed of 33 m/s...
A ball is thrown toward a cliff of height h with a speed of 33 m/s and an angle of 60 ? above horizontal. It lands on the edge of the cliff 3.7 s later. How high is the cliff? What was the maximum height of the ball? What is the ball's impact speed?
A basketball is shot from an initial height of 2.40 m with an initial speed v0...
A basketball is shot from an initial height of 2.40 m with an initial speed v0 = 14 m/s directed at an angle θ0 = 30 ∘ above the horizontal. How far from the basket was the player if he made a basket? At what angle to the horizontal did the ball enter the basket?
A ball is thrown toward a cliff of height h with a speed of 30 m/s...
A ball is thrown toward a cliff of height h with a speed of 30 m/s and an angle of 60∘ above horizontal. It lands on the edge of the cliff 3.0 s later. a) How high is the cliff? b) What was the maximum height of the ball? c) What is the ball's impact speed?
1.Determine a formula for the maximum height h that a rocket will reach if launched vertically...
1.Determine a formula for the maximum height h that a rocket will reach if launched vertically from the Earth's surface with speed v0(<vesc). Express in terms of v0,rE,ME, and G. 2. How high does a rocket go if 8.60 km/s ? Ignore air resistance and the Earth's rotation.
A small object begins a free-fall from a height of H = 86.5 m at t0...
A small object begins a free-fall from a height of H = 86.5 m at t0 = 0s. After tau = 2.65s, a second small object is launced vertically up from the ground with the initial velocity v0 = 41.2 m/s. At what height from the gound will the two objects first meet?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT