Question

What fraction of 5 MeV *α* particles will be scattered
through angles greater than 12° from a gold foil (*Z* = 79,
density = 19.3 g/cm^{3}) of thickness 10^{-8}
m?

Answer #1

Fraction of incident particle scattered by an angle and greater is given as:

Where,

t = thickness =

Z_{1}e = charge of alpha particle = 2e

Z_{2}e= charge of gold foil = 79e

K = kinetic energy of alpha particle

n = density of target particles

Which is given as:

Where,

Density

(i.e 1 in this case)

Gram molecular weight =

By putting values n will be :

Now,

By putting the values value of fraction is:

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