Question

1. A ray of sunlight is passing from diamond into crown glass; the angle of incidence is 35.00°. The indices of refraction for the blue and red components of the ray are: blue (n_diamond = 2.444, n_{crown glass} = 1.531), and red (n_diamond = 2.410, n_{crown glass} = 1.520). Determine the angle between the refracted blue and red rays in the crown glass.

2. An object is 25 cm in front of a diverging lens that has a focal length of -17 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.3?

3. Two identical diverging lenses are separated by 21 cm. The focal length of each lens is -12 cm. An object is located 3.2 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right.

4. A woman can read the large print in a newspaper only when it is at a distance of 57 cm or more from her eyes. (a) Is she nearsighted (myopic) or farsighted (hyperopic), and what kind of lens is used in her glasses to correct her eyesight? (b) What should be the refractive power (in diopters) of her glasses (worn 2.6 cm from the eyes), so she can read the newspaper at a distance of 24 cm from the eyes?

Answer as specific as possible, please!

Answer 1

1.

For Blue ray :

i = angle of incidence = 35.00

r_b = angle of refraction for blue

n_diamond = 2.444

n_crownglass = 1.531

Using snell's law

n_diamond Sini = n_crownglass Sinr_b

(2.444) Sin35 = (1.531) Sinr_b

r_b = 66.2944993 deg

For Red ray :

i = angle of incidence = 35.00

r_r = angle of refraction for red

n_diamond = 2.410

n_crownglass = 1.520

Using snell's law

n_diamond Sini = n_crownglass Sinr_r

(2.410) Sin35 = (1.520) Sinr_b

r_r = 65.42546025 deg

r = angle between refracted blue and red ray = r_b - r_r = 66.2944993 - 65.42546025

r = 0.869 deg