Question

An object is 15.4 cm in front of a thin converging lens that has a focal length equal to 10.0 cm. A concave mirror that has a radius equal to 10.0 cm is 23.8 cm in back of the lens.

(a) Find the position of the final image formed by the mirror-lens combination.
cm from the lens, on the same side as the original object.

Answer 1

a)

let f1 = 10 cm

u1 = 15.4 (object distance for lens)

let v1 is the image distance of first lense

Apply 1/u1 + 1/v1 = 1/f1

1/v1 = 1/f1 - 1/u1

1/v1 = 1/10 - 1/15.4

v1 = 28.5 cm

object distance for the mirror, u2 = -(28.5 -23.8)

= -4.7 cm

f2 = 10 cm

let v2 is the image distance for the second mirror

Apply, 1/u2 + 1/v2 = 1/f2

1/v2 = 1/f2 - 1/u2

1/v2 = 1/(10) - 1/(-4.7)

v2 = 3.2 cm <<<<<<<<<<<<<-------------------Answer