Question

A parallel-plate capacitor has plates of area 0.16 m2 and a
separation of 1.20 cm. A

battery charges the plates to a potential difference of 180 V and
is then

disconnected. A dielectric slab of thickness 0.4 cm and dielectric
constant K=3 is

then placed symmetrically between the plates.

a) What is the capacitance before the slab is inserted?

b) What is the capacitance with the slab in place?

c) What is the free charge q before the slab is inserted?

d) What is the free charge q after the slab is inserted?

e) What is the magnitude of the electric field in the space between
the plates

and dielectric?

f) What is the magnitude of the electric field in the dielectric
itself?

g) With the slab in place, what is the potential difference across
the plates?

h) How much external work is involved in the process of inserting
the slab?

i) What is the minimum dielectric strength that the dielectric must
withstand

so that it will not break when it is placed in the capacitor?

j) Assume that I repeat the process (charge my initial capacitor to
the same

battery, then remove the battery) but then instead of introducing a
slab of

dielectric I introduce an identically shaped slab made out of solid
copper.

How will any of the answers to questions b), d), e), f), g) and h)
?

Answer #1

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circular, with radius 3.00 cmcm. The capacitor is connected to a
battery and a charge of magnitude 25.0 pCpC goes onto each plate.
With the capacitor still connected to the battery, a slab of
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A parallel-plate capacitor filled with air
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