A concave mirror has a focal length of 36.4 cm. The distance between an object and its image is 52.6 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror.
focal length f = 36.4 cm
If object is beyond center of curvature
the image is real
s - s' = 52.6 cm
s = object distance
s' = image distance
s' = s - 52.6
part(a)
from mirror equation
1/s + 1/s' = 1/f
1/s + 1/(s-52.6) = 1/36.4
object distance s = 107.6 cm
part (b)
image distance s' = s - 52.6
image distance s' = 107.6 - 52.6 = 55 cm
===========================
part (c)
If object is between focal point and mirror
the image is virtual
image distance distance is negative
s + s' = 52.6 cm
s = object distance
s' = image distance
s' = 52.6 - s
part(c)
from mirror equation
1/s + 1/s' = 1/f
1/s - 1/(52.6 - s) = 1/36.4
object distance s = 17.8 cm
part (d)
image distance s' = 52.6 - 17.8
image distance s' = 34.8 cm
Get Answers For Free
Most questions answered within 1 hours.