Question

Two vertical wires are parallel to each other and a distance D=10cm from each other. They both flow current 16A in the same direction, going up.

Determine the absolute value of the total magnetic field at a point located between the two wires, at a distance L=2cm from the leftmost wire. Express your answer in µT.

Answer 1

Magnetic field due to current carrying wire is given by,

B = *I/(2*pi*d)

direction of magnetic field is given by right hand rule.

Since, both flow current in the same direction, going up.

So, Magnetic field at mid point qill be:

Bnet = B1 - B2

Bnet = *I1/(2*pi*d1) - *I2/(2*pi*d2)

given, I1 = I2 = 16 A

d1 = distance from wire 1 = 2 cm = 0.02 m

d2 = distance from wire 2 = D - d1 = 10 - 2 = 8 cm = 0.08 m

= 4*pi*10^-7

then,

Bnet = [/(2*pi)]*(I1/d1 - I2/d2)

Bnet = (2*10^-7)*(16/0.02 - 16/0.08)

Bnet = 12*10^-5 T

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