You want to get an idea of the magnitude of magnetic fields produced by overhead power lines. You estimate that a transmission wire is about 11m above the ground. The local power company tells you that the line operates at 13kV and provide a maximum of 57MW to the local area.
A) Estimate the maximum magnetic field you might experience walking under such a power line, and compare to the Earth's field. [For an ac current, values are rms, and the magnetic field will be changing.]
B) Compare to the Earth's field of 5.0
A)
Volatage of the line, V = 13 kV = 13*10^4 V
Power , P = 57 MW = 57*10^6 W
distance from the ground , d = 11 m
We know,
Magnetic field due to a current carrying wire at a distance d from the wire is give by :
B = uI/(2*pi*d)
where u = 1.26*10^-6
I = current in the wire
pi = 3.14
We also know,
Power, P = V*I
So, I = P/V = 57*10^6/(13*10^3) = 4384.6 A
So, B = 1.26*10^-6*(4384.6)/(2*3.14*11) = 8*10^-5 T <------answer
B)
So, it is about = (8/5) = 1.6 times than the Earth's field <--------answer
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