Question

ector   is 2.2 cm long and is 30.0° above the positive x-axis. Vector is 1.4 cm long and is 60.0° below the positive x-axis. If  , then the magnitude of is

Answer 1

Given:

for vector 1:

magnitude A = 2.2cm

direction is 30° above X axis

for vector 2:

magnitude B = 1.4cm

direction is 60° below X axis

So, angle between them is:

© = 30° +60°

© = 90°

So, magnitude of resultant of the above two vectors will be:

R = √{A^{​​​​​​2}+B^{​​​​​​2}​​​+2ABcos©}

Now cos© = cos90° = 0

R= √{A^{​​​​​​2}+B^{​​​​​​2}​​​}

R = √(2.2² + 1.4²)

R = √6.8

R = 2.60768 cm

This is the magnitude of resultant of the two given vectors.

(Feel free to ask for any doubts, and please like or dislike the answer according to your experience. Thank you.)