Question

An electron is to be accelerated in a uniform electric field having a strength of 1.8

Answer 1

apply the relation between electric field and Potnetal V as E = V/d

so here Potnetial differende V = E d

V = 1.8 e 6 * 0.45

V = 810000 volts

so

now user the relation of change in KE = PE

chnage in KE = eV

Ke = 1.6 e-19 * 810000

Ke change = 1.296 *10^-13 Joules

as 1 eV = 1.6 e -19 J

KE chnage = 1.296 e -13/1.6 e -19

KE = 810 KeV

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given PE = Vq = 42.5 e 9 eV

so

so Potential V = 42.5 e 9 Volts

so as E = V/d

d = V/E

d = 42.5 e 9/1.8 e6

d = 23.61 km