Four capacitors are placed within an 18.0 V circuit as follows:
Two capacitors 30.0 μF and 65.0 μF are connected in series with the battery, followed by two capacitors 45.0 μF and 80.0 μF connected in parallel.
Being as specific and detailed as possible (without performing any calculations!),
How the equivalent capacitance in this circuit would change if the two capacitors originally in series were now connected in parallel, and the two capacitors originally connected in parallel were now connected in series, and placed within an 18.0 V circuit
If you have any doubt then mention in the commant.
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