Two open tubes both have actual length
1 m, but their diameters are D1 = 1 cm and D2 = 10 cm. Allowing for end corrections,
what are their fundamental frequencies? Don't forget that the tubes are open on both
The wavelength of the fundamental frequency for a completely open pipe is twice the length of the tube: = 2l or l = /2.
Considering end correction the expression for : = 2L + 4C
The equation relating the wavelength of a wave, to the frequency of the wave : v = f
The end correction for open tube = D/2
Speed of sound is 343 m/s
Case 1, D1 = 1 cm = 0.01 m
= 2*1 + 4* (0.01/2) = 2.02 m
Thus f = v / = 343/2.02 = 169.8 Hz
Case 2 D2 = 10 cm = 0.1 m
= 2*1 + 4* (0.1/2) = 2.2 m
Thus f = v / = 343/2.2 = 155.91 Hz
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