Answer:-
As we know that the electric field is given by,
E = 1/4(q/r^2)
Where, E = Electric Field intensity
q= charge
And r= distance from charge
But here, r = and q = nC
So, E = 1/4[n/()^2]
As, 1/= 0
So, E = 0N/C Ans.
So, there will be negligible electric field intensity at that place.
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