Question

A violin string of length 40 cm and mass 1.4 g has a frequency of 526 Hz when it is vibrating in its fundamental mode. (a) What is the wavelength of the standing wave on the string? (b) What is the tension in the string? (c) Where should you place your finger to increase the frequency to 676 Hz?cm from the fixed end of the string (from the peg of the violin)

Answer 1

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

A violin string of length 40 cm and mass 1.5 g has a frequency of 455 Hz when it is vibrating in its fundamental mode.
(a) What is the wavelength of the standing wave on the string?
cm

(b) What is the tension in the string?
N

(c) Where should you place your finger to increase the frequency to 605 Hz?
cm from the fixed end of the string (from the peg of the violin)   

a)? = 2L = 2*40 = 80 cm
b) v = f? = 455*0.8 = 364m/s
v = ?(T/?)
364 = ? (T / (0.0015/0.4) )
T = 496.86 N

c)f = 605 Hz

? = v/f = 324/605 = 0.6m = 60 cm

so finger should be kept at (60/2)=30 cm from fixed end