Question

Projectile Physic lab Table 1: Trial 1 Trial 2 Trial 3 Average Time (s) 0.4179 0.4032...

Projectile Physic lab

Table 1:

Trial 1

Trial 2

Trial 3

Average

Time (s)

0.4179

0.4032

0.4524

0.4245

Horizontal distance (m)

0.48

0.48

0.48

0.48

Vertical distance (m)

0.93

0.93

0.93

0.93

Table 2 :

Trial 1

Trial 2

Trial 3

Average

Time (s)

0.4915

0.4782

0.4473

0.4723

Horizontal distance (m)

0.40

0.37

0.35

0.37

Vertical distance (m)

0.93

0.93

0.93

0.93

1- Calculate the initial and final speed of the ball using Newton’s second law for both tables.

2- Calculate the gravitation acceleration g practically for both tables.

3- Find the percentage error for the value of g found in the above question, knowing that the true value is 9.8.

Homework Answers

Answer #1

The first table gives a time of 0.4245 s (4 significant figures), horizontal distance of 0.48 m (2 sig fig) and vertical distance of 0.93 m (2 sig fig)

The total distance is thus:

We should round this off later.

The initial speed is just this distance divided by time taken.

We need to round this off to 4 significant figures.

thus, speed = 2.465 m/s

Applying the same logic for the second table,

and thus speed is:

When rounded to 4 sig figures, we have speed = 2.119 m/s

---------------------

The formula for horizontal distance is:(using first table)

we know that:

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Data Table 3: Time Trials to Drop an Object 2m Item Data Trial 1 Drop time,...
Data Table 3: Time Trials to Drop an Object 2m Item Data Trial 1 Drop time, t, (s) 0.69 Trial 2 Drop time, t, (s) 0.73 Trial 3 Drop time, t, (s) 0.73 Trial 4 Drop time, t, (s) 0.71 Trial 5 Drop time, t, (s) 0.73 Trial 6 Drop time, t, (s) 0.72 Trial 7 Drop time, t, (s) 0.71 Trial 8 Drop time, t, (s) 0.75 Trial 9 Drop time, t, (s) 0.69 Trial 10 Drop time, t,...
A projectile is fired with an initial speed of 64.0 m/s at an angle of 41.2...
A projectile is fired with an initial speed of 64.0 m/s at an angle of 41.2 ∘ above the horizontal on a long flat firing range. 1. Determine the maximum height reached by the projectile. 2.Determine the total time in the air. 3. Determine the total horizontal distance covered (that is, the range). 4. Determine the speed of the projectile 1.63 s after firing. 5. Determine the direction of the projectile 1.63 s after firing.
1. Can someone just double check my results? For table 1 I needed to find the...
1. Can someone just double check my results? For table 1 I needed to find the velocity for each trial. 2. For table 2 I was asked to find horizontal velocity. 3. For table 3 I was asked to find the average time, range, and compute velocity. Table 1: Timing Data of Ball on Table Distance between tape strips =  10 inches   in meters = 0.254 m Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Time (s) .32s .35s .50s...
A projectile is fired with an initial velocity of 75.0 m/s at an angle of 33.0...
A projectile is fired with an initial velocity of 75.0 m/s at an angle of 33.0 degrees above the horizontal. It lands on a hillside 50m above the level from which it was fired. Determine 1) the time of flight of the projectile. 2) the maximum height to which it rises. 3) the horizontal distance from launching to landing points.
Motion of the CM, 2D:a)Review question: Projectile 1 is fired upward with initial speed 240 m/s,...
Motion of the CM, 2D:a)Review question: Projectile 1 is fired upward with initial speed 240 m/s, at an angle of 60° above the horizontal. It lands later on the horizontal ground a distance x away. Find x. Show your setup and work. b)An identical projectile 2 is fired with the same initial speed and angle. However at the highest point of its path, it explodes into two pieces, 2A and 2B, each with half the original mass. The explosion forces...
Displacement (meters) Time (seconds) Trial 1 (0.70 m) 0.695 m 0.373 s 0.695 m 0.374 s...
Displacement (meters) Time (seconds) Trial 1 (0.70 m) 0.695 m 0.373 s 0.695 m 0.374 s 0.695 m 0.373 s 0.695 m 0.373 s Average Displacement = 0.6951 m Average Time = 0.3733 s Trial 2 (0.60 m) 0.598 m 0.345 s 0.595 m 0.345 s 0.595 m 0.345 s 0.598 m 0.346 s Average Displacement = 0.5960 m Average Time = 0.3453 s Trial 3 (0.50 m) 0.495 m 0.314 s 0.495 m 0.315 s 0.495 m 0.314 s...
Displacement (meters) Time (seconds) Trial 1 (0.70 m) 0.695 m 0.373 s 0.695 m 0.374 s...
Displacement (meters) Time (seconds) Trial 1 (0.70 m) 0.695 m 0.373 s 0.695 m 0.374 s 0.695 m 0.373 s 0.695 m 0.373 s Average Displacement = 0.6951 m Average Time = 0.3733 s Trial 2 (0.60 m) 0.598 m 0.345 s 0.595 m 0.345 s 0.595 m 0.345 s 0.598 m 0.346 s Average Displacement = 0.5960 m Average Time = 0.3453 s Trial 3 (0.50 m) 0.495 m 0.314 s 0.495 m 0.315 s 0.495 m 0.314 s...
could you please solve it with shiwing the full work 1- A high powered projectile is...
could you please solve it with shiwing the full work 1- A high powered projectile is fired horizontally from the top of a cliff at a speed of 638.6 m/s. Determine the magnitude of the velocity (in m/s) after 5 seconds. Take gravitational acceleration to be 9.81 m/s2. 2- A man throws a ball with a velocity of 20.9 m/s upwards at 33.2° to the horizontal. At what vertical distance above the release height (in metres) will the ball strike...
1) On Planet #1, you drop a stone from rest, 94.9 m above the ground, and...
1) On Planet #1, you drop a stone from rest, 94.9 m above the ground, and the stone hits the ground 2.96 s later. What is the value of g on Planet #1? 2)On planet #2, you launch a projectile straight up from the ground at a speed of 32.6 m/s. The projectile reaches a maximum height of 68.0 m before falling back to the ground. What is the value of g for planet #2? 3)On planet #3, you fire...
1. A 2 kg ball drops from a height of 0.5 m to the table. What...
1. A 2 kg ball drops from a height of 0.5 m to the table. What will be the kinetic energy of the ball just before it hits the table? (assume g= 9.8 m/s2) Group of answer choices 9.8 J 49.0 J 20.1 J 124 J 24.5 J 2. Convert the velocity of 100 miles per hour into meters per second using 1 mile = 1600 meter, and 1 hour = 3600 seconds Group of answer choices 99.9 m/s 44.4...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT