Question

a 2500 kg car accelerates uniformly from rest to 15.0 m/s in 8.00 s. What is...

a 2500 kg car accelerates uniformly from rest to 15.0 m/s in 8.00 s.

  1. What is the work done on the car in this time interval?
  2. What is the power delivered by the engine in this time interval?

Answer in 3 decimal places, and include full equation please

Homework Answers

Answer #1

In the given problem

a)Work done on the car can be find using below formula

b)power delivered by engine,

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 16.0 m/s in 12.9 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. ____ hp (b) Find the instantaneous power output of the engine at t = 12.9 s, just before the car stops accelerating. ______ hp
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7...
A 1.50 ✕ 103-kg car starts from rest and accelerates uniformly to 15.1 m/s in 12.7 s. Assume that air resistance remains constant at 400 N during this time. (a) Find the average power developed by the engine. (hp) (b) Find the instantaneous power output of the engine at t = 12.7 s, just before the car stops accelerating. (hp)
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch...
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch of road. Ignoring friction , determine the average power required to accelerate the car if the mass of the car is 1,131 kg
A 1,500 kg car starts from rest and accelerates to 23 m/s in 11 s. Assume...
A 1,500 kg car starts from rest and accelerates to 23 m/s in 11 s. Assume that the air resistance remains constant at 162 N. Calculate the acceleration of the car. Calculate the average force exerted by engine during this time. Calculate the average velocity of the car. Calculate the average power output during this time.
A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s...
A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0 s. How strong must the rope be?     mk = 0.373
A car accelerates uniformly from rest to 17.9 m/s in 6.31 s along a level stretch...
A car accelerates uniformly from rest to 17.9 m/s in 6.31 s along a level stretch of road. Ignoring friction, determine the average power required to accelerate the car if (a) the weight of the car is 8.28 x 103 N, and (b) the weight of the car is 1.58 x 104 N.
An initially stationary 3.8 kg object accelerates horizontally and uniformly to a speed of 14 m/s...
An initially stationary 3.8 kg object accelerates horizontally and uniformly to a speed of 14 m/s in 3.6 s. In that 3.6 s interval, how much work is done on the object by the force accelerating it? What is the instantaneous power due to that force at the end of the interval? What is the instantaneous power due to that force at the end of the first half of the interval?
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9...
a) A car accelerates uniformly from rest and reaches a speed of 13.7 m/s in 10.9 s. The diameter of a tire is 71.8 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev. b) What is final rotational speed of a tire? Answer in units of rev/s.
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s....
A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.05 s. Assume the diameter of a tire is 59.0 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s
"A 2000-kg car accelerates from 20 to 60 km/h on an uphill road. The car travels...
"A 2000-kg car accelerates from 20 to 60 km/h on an uphill road. The car travels 120 m and the slope of the road from the horizontal is 25 degrees. Determine the work done by the engine." The answer is 1240 kJ using the First Law of Thermodynamics, but please explain sign conventions of Work and whether or not the engine is excluded from the system... thank you