Question

1. A woman can read the large print in a newspaper only when it
is at a distance of 57 cm or more from her eyes.
**(a)** Is she nearsighted (myopic) or farsighted
(hyperopic), and what kind of lens is used in her glasses to
correct her eyesight? **(b)** What should be the
refractive power (in diopters) of her glasses (worn 2.6 cm from the
eyes), so she can read the newspaper at a distance of 24 cm from
the eyes?

2. An object is 25 cm in front of a diverging lens that has a focal length of -17 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.3?

Answer as specific as possible, please!

Answer #1

A woman can read the large print in a newspaper only when it is
at a distance of 56 cm or more from her eyes. (a) Is she
nearsighted (myopic) or farsighted (hyperopic), and what kind of
lens is used in her glasses to correct her eyesight? (b) What
should be the refractive power (in diopters) of her glasses (worn
2.2 cm from the eyes), so she can read the newspaper at a distance
of 26 cm from the eyes?

A woman can read the large print in a newspaper only when it is
at a distance of 55 cm or more from her eyes. (a) Is she
nearsighted (myopic) or farsighted (hyperopic), and what kind of
lens is used in her glasses to correct her eyesight? (b) What
should be the refractive power (in diopters) of her glasses (worn
3.0 cm from the eyes), so she can read the newspaper at a distance
of 25 cm from the eyes?

1. A ray of sunlight is passing from diamond into crown glass;
the angle of incidence is 35.00°. The indices of refraction for the
blue and red components of the ray are: blue
(ndiamond = 2.444, ncrown
glass = 1.531), and red (ndiamond =
2.410, ncrown glass = 1.520). Determine the
angle between the refracted blue and red rays in the crown
glass.
2. An object is 25 cm in front of a diverging lens that has a
focal length...

a woman can read the large print in a newspaper only
when it is at a distance of 70cm or more from her eyes.
calculate the refractive power of the lens required to correct this
defect (assume that the corrective lenses are worn 2cm from her
eyes)

Contact lenses are placed right on the eyeball, so the distance
from the eye to an object (or image) is the same as the distance
from the lens to that object (or image). A certain person can see
distant objects well, but his near point is 50.0 cm from his eyes
instead of the usual 25.0 cm .
Part A
Is this person nearsighted or farsighted?
Is this person nearsighted or farsighted?
This person is nearsighted.
This person is farsighted....

(1)(A)Your physics study partner is nearsighted. She has a near
point of 50.0 cm from her eyes and she wears eyeglasses designed to
allow her to read a newspaper held at a distance of 22.5 cm from
her eyes. Determine the focal length of her glasses for each of the
following cases. She wears her eyeglasses 1.80 cm from her eyes.
She wears her eyeglasses 2.80 cm from her eyes.
(B)What magnification is produced by a 0.150 cm focal length...

Without her glasses, Dr.D.’s myopic eyes can only image objects
that are, at most, 18.5cm awayfrom her eye(this is called her “far
point”). Her “near point” (the closest she can image an object) is
10.5 cm from her eye. With this range of vision, she obviously
needs glasses. Let’s say we want her glasses to allow her to see an
object 20 feet away(not really the same as “20/20” vision.... but
close enough).
You also need to note her glasses...

1. What is the optical power of the eye when viewing an object
from a distance of 23.5 cm?
2.What is the far point for a person whose eyes have a relaxed
power of 50.25 D?
3. What power lens is required to correct a myopic (nearsighted)
eye with a far point of 6.50 m? Neglect the distance between the
corrective lens and the eye.
4. What power lens is required to correct a hyperopic
(farsighted) eye with a...

A pair of glasses is designed for a person with a far-point
distance of 4 m so that she can read street signs 19.5 m away. (The
far-point distance is the distance from the eye at which you are
just able to properly focus a distant object.)
(a) If the glasses are to be worn 1.0 cm from her eyes, what is
the needed focal length? Answer: -5.02 m
(b) Compare this focal length (find the percent difference) to
the...

2. Correcting vision: quantitative. Corrective lenses work
because the lens bends light such that it, combined with the eye
itself, light forms a clear image on the retina. Another way to
think about this is that the corrective lens (glasses) form an
image of the object at a location where the eye can see clearly
without corrective lenses. For a nearsighted person viewing an
object very far away (object at infinity), the lens corrective lens
creates an image at the...

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