Question

A wire with a length of 2.7 m and a mass of 0.75 kg is in a region of space within a magnetic field of 0.84 T. What is the minimum current needed to levitate the wire?

Answer #1

Set the magnitude of the magnetic force equal to the weight of the wire to find the current required to levitate the wire. The force is maximum when the current is perpendicular to the field. Therefore, the minimum required current occurs in the perpendicular configuration.

Set the magnetic force equal to the weight:

Solving for I

the minimum current needed to levitate the wire is 3.241Amperes

This physics setup is related to that used for magnetic levitation trains. A pretty substantial field (0.84 T is 16,800 times stronger than Earth

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