Question

The manager of an airport has a 2,400 gal steel tank. He accepts a delivery of gasoline when the temperature is 29oC. A cool front comes by and the temperature goes down to 1oC before the gasoline is sold. At $3.15/gal how much, in dollars, has the airport lost in the transaction? (\alpha=0.58\times 10^{-3}/ ^oF)

Answer #1

Here, =0.58*10^-3 /F

Now, coefficient of volume expansion = 3 = 3*0.58*10^-3 =1.74*10^-3 /F

V=V**T, where V is change in volume, V is original volume, is coefficient of volume expansion and T is change in temperature.

Here,V=2,400 gal , =1.74*10^-3 /F, T=29-1=28 deg. C = 1.8*28 Fdeg. F=50.4 deg. F.

So, V=2400*1.74*10^-3*50.4=210.47 gal.

Hence, loss= $3.15*210.47=$663.

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