A system of forces consists of Fi ( 20N , 40 " ) and F2 ( 20N , 160 ° ) . The direction of the third force Fz ( in N ) , which balances * the two forces Fi and F2 , is
X component of 20N is 20cos40 and y component is 20sin40
X and y component of other 20N are 20cos160 and 20 sin160
Resultant x component is Fx=20cos40+20cos160=-3.47N(in negative X direction )
Resultant y component Fy=20sin40+20sin140=19.7N(positive y direction )
Let F be the resultant of Fx and Fy
Angle between F and Fx
Tan=Fy/Fx=19.7/(-3.47)=-5.677
=-80
Hence the third force Fz should be in opposite direction of F. That is F is at -(80+180)=-260degree from negative x axis in clockwise direction OR at -80degree clockwise from positive x axis in clockwise direction
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