Electrostatic force is given by:
F = k*q1*q2/d^2
q1 = 2.3 C = 2.3*10^-6 C
q2 = -1.2 C = -1.2*10^-6 C
d = distance between both charges = ?
F = attractive force between both charges = 1.5 N
k = electrostatic force constant = 9*10^9
So,
d^2 = k*q1*q2/F
d^2 = 9*10^9*2.3*10^-6*1.2*10^-6/1.5
d^2 = 0.01656
d = sqrt (0.01656) = 0.1287 m
Since first charge is at origin, So second charge should be at x = 0.1287 m = 12.87 cm
In two significant figures
x = 0.13 m = 13 cm
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