Question

Three charged particles are located at the corners of an
equilateral triangle as shown in the figure below (let *q* =
2.80 µC, and *L* = 0.790 m). Calculate the total electric
force on the 7.00-µC charge.

magnitude | N |

direction | ° (counterclockwise from the
+x axis) |

Three charged particles lie in the *x* *y*
coordinate plane at the vertices of an equilateral triangle with
side length *L*.

- Positive charge
*q*is at the origin. - A charge of 7.00 µC is in the first quadrant, along a line
60.0° counterclockwise from the positive
*x*-axis. - A charge of −4.00 µC is at (
*L*, 0).

Answer #1

Here we have to apply formula of force between two charged particles along with proper direction

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Image:
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Pls show work

Three charges are at the corners of an equilateral triangle, as
shown in the figure below. Calculate the electric field at a point
midway between the two charges on the x-axis. (Let Let q1 = 7.00
μC, q2 = 4.50 μC, and q3 = −3.00 μC.
magnitude =? (N/C)
direction = ? (below the x-axis)

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