Question

A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used in combination. The converging lens has a focal length of 15.2 cm. The diverging lens is of unknown focal length. An object is placed 19.3 cm in front of the converging lens; the final image is virtual and is formed 12.0 cm in front of the diverging lens. What is the focal length of the diverging lens?

Answer #1

A diverging lens with a focal length of -19.7 cm and a
converging lens with a focal length of 11.0 cm have a
common central axis. Their separation is 39.5 cm. An
object of height 1.1 cm is 26.4 cm in front of
the diverging lens, on the common central axis. Find the location
of the final image produced by the combination of the two
lenses.
Where is the image located as measured from the converging
lens?
What is the...

A) An object is placed 26 cm in front of a converging lens of
focal length 5 cm. Another converging lens of focal length 10 cm is
placed 20 cm behind the first lens.
1) Find the position of the final image with respect to the second
lens. ____cm
2) Find the magnification of the final image. _____
B) A diverging lens of focal length −12cm projects the image of
an object onto a wall. What is the object distance if...

A diverging lens with a focal length of -15 cm and a converging
lens with a focal length of 15 cm have a common central axis. Their
separation is 12 cm. An object of height 1.0 cm is 10 cm in front
of the diverging lens, on the common central axis.
(a) Where does the lens combination produce the final image of
the object (the one produced by the second, converging lens)?
in cm
(b) What is the height of...

A diverging lens with a focal length of -11.3 cm and a
converging lens with a focal length of 14.6 cm have a common
central axis. Their separation is 30.9 cm. An object of height 1.0
cm is 33.1 cm in front of the diverging lens, on the common central
axis. Find the location of the final image produced by the
combination of the two lenses.
Where is the image located as measured from the converging
lens?
What is the...

An
object is placed 5cm in front of a diverging lens of focal length
25 cm. A second converging lens of focal length 15cm is positioned
20 cm to the right of the first lens. What is the final image
distance? What is the magnification of the final image? Is it
upright of inverted? Real or virtual?

A 2.05-cm-tall object is placed 30.0 cm to the left of a
converging lens with a focal length f1 = 20.5 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
Q:How tall is the final image of the object?

An object is placed 78.1 cm in front of a diverging lens with a
focal length of magnitude 37.3 cm. A converging lens having a focal
length of magnitude 27.49 cm is placed 105.3 cm past the first
lens. Where is the final image formed. Is this image Real or
Virtual. Inverted or Non-Inverted? Also calculate the
magnification.

A 2.05-cm-tall object is placed 30.0 cm to the left of
a converging lens with a focal length f1 = 21.0 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
How tall is the final image of the object?________cm

A converging lens with a focal length of 20 cm and a diverging
lens with a focal length of -34 cm are 74.0 cm apart. A 2.6-cm-tall
object is 40 cm in front of the converging lens.
1. Calculate the distance between image and diverging lens.
2. Calculate the image height.

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

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