A cannon is fired over level ground with its barrel at an angle of 45.0o to the horizontal. The shell takes 51 s to hit the ground. Neglect air resistance and the height of the muzzle. How far from the cannon did the shell land? The units are not in the mks system here, but the answer is unambiguous.
When the shell lands, the vertical displacement is zero. We use
this to find the initial launch speed. In the horizontal direction,
the velocity will be constant because there is no acceleration in
horizontal direction. We use this to find the required distance
from the canon where the shell lands.
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