Question

- The velocity of a particle (m = 10 mg, q = -4.0 mC) at t...

- The velocity of a particle (m = 10 mg, q = -4.0 mC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a uniform electric field of 20 N/C in the positive x direction, what is the particle's speed at t = 5.0 s? What is the distance the particle moves in the field?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Acceleration of

Final Velocity, v = u + at

v = 20 + (-8)(5) = -20m/s

The velocity of the particle becomes zero; v = u + at

0 = 20 + (-8)t

t = 2.5s

Using equation,

Distance covered in 2.5s

  
Distance covered in next 2.5s

Total distance covered in 5s = (25 + 25) = 50m

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The velocity of a particle (m = 10 mg, q = –4.0 μC) at t =...
The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 30 m/s in the positive x direction. If the particle moves in a uniform electric field of 20 N/C in the positive x direction, what is the particle's speed (in m/s) at t = 5.0 s?
A particle (q = -4.0 μC, m = 5.0 mg) moves in a uniform magnetic field....
A particle (q = -4.0 μC, m = 5.0 mg) moves in a uniform magnetic field. If the magnetic field strength is B, the speed of the particle is v, and the angle that the particle’s velocity makes with the magnetic field direction is q, in which of the following cases would the magnitude of the particle’s acceleration be the largest? A. v = 2.0 km/s, B = 9.1 mT, q = 90° B. v = 2.0 km/s, B =...
A particle (q = 3.0 mC, m = 20 g) has a speed of 20 m/s...
A particle (q = 3.0 mC, m = 20 g) has a speed of 20 m/s when it enters a region where the electric field has a constant magnitude of 80 N/C and a direction which is the same as the velocity of the particle. What is the speed of the particle 3.0 s after it enters this region? A charge of 80 nC is uniformly distributed along the x axis from x = 0 to x = 0 m....
A small particle with positive charge q=+4.25×10^−4 C and mass m=5.00×10^−5 kg is moving in a...
A small particle with positive charge q=+4.25×10^−4 C and mass m=5.00×10^−5 kg is moving in a region of uniform electric and magnetic fields. The magnetic field is B=4.00 T in the +z-direction. The electric field is also in the +z-direction and has magnitude E=60.0 N/C. At time t = 0 the particle is on the y-axis at y=+1.00 m and has velocity v = 30.0 m/s in the +x-direction. Neglect gravity. What are the x-, y-, and z-coordinates of the...
Thanks in advance, I couldn't find the answers to the following questions: Q1) A particle (q...
Thanks in advance, I couldn't find the answers to the following questions: Q1) A particle (q = –4.0 µC, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have a magnetic force with a magnitude of 29 ?N. What is the magnitude of the magnetic field? Q2) An electron has a velocity...
A particle with positive charge q = 2.56 10-18 C moves with a velocity v with...
A particle with positive charge q = 2.56 10-18 C moves with a velocity v with arrow = (3î + 5? ? k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B with arrow = (3î + 5? + k) T and E with arrow = (2î ? ? ? 5k) V/m. Fx = N Fy = N Fz = N (b)...
A 6.70 −μC particle moves through a region of space where an electric field of magnitude...
A 6.70 −μC particle moves through a region of space where an electric field of magnitude 1200 N/C points in the positive x direction, and a magnetic field of magnitude 1.25 T points in the positive z direction. If the net force acting on the particle is 6.21×10−3 N in the positive xx direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane. vx, vy, vz =   answer is 0,219,0 m/s why is...
A 6.60 −μC particle moves through a region of space where an electric field of magnitude...
A 6.60 −μC particle moves through a region of space where an electric field of magnitude 1250 N/C points in the positive x direction, and a magnetic field of magnitude 1.01 T points in the positive z direction. 1. If the net force acting on the particle is 6.25×10^−3 N in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane. vx, vy, vz =   m/s  
A particle with positive charge q = 4.49 10-18 C moves with a velocity v =...
A particle with positive charge q = 4.49 10-18 C moves with a velocity v = (3î + 5ĵ − k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (5î + 2ĵ + k) T and E = (5î − ĵ − 2k) V/m. (Give your answers in N for each component.) Fx = N Fy = N Fz =...
An electron is traveling through a uniform electric field. The constant electric field is given by...
An electron is traveling through a uniform electric field. The constant electric field is given by . At t = 0, the electron is at (0, 0) and traveling in the positive z direction with a speed of 5 m/s. a) What is its position 5.0 s later? b) What is the magnitude and direction of the particle's velocity at 5.0 s? EDIT: Oops! E = (-3.00 x 10^-11 N/C)i - (2.00 x 10^-11 N/C) j + (1.00 x 10^-11...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT