Question

Calculate the kinetic energy that the earth
(*M** _{E}* = 5.98× 10

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Calculate the kinetic energy that the earth has because of (a)
its rotation about its own axis and (b) its motion around the sun.
Assume that the earth is a uniform sphere and that its path around
the sun is circular. For comparison, the total energy used in the
United States in one year is about 1.1 x 1020 J.

Calculate the KE that the earth has because of a) it's rotation
about its own axis and b) its morion around the sun. Assume that
the earth is a uniform sphere and that its path around the sun is
circular. for comparison, the total energy used in the US in one
year is about 1.1 x 10^20 J.

For the purposes of this problem, treat the Earth as a solid,
uniform sphere with mass 5.97×1024 kg and radius
6.37×106 m, and assume that the Earth's orbit around the
sun is circular with a radius of 1.5×1011
m.
(A) What is the angular kinetic energy of the Earth due to its
orbit around the sun?
(B) What is the magnitude of the Earth's angular momentum due to
its orbit around the sun?
(C) What is Earth's angular kinetic energy...

A satellite is in a circular orbit about the earth (ME = 5.98 x
1024 kg). The period of the satellite is 1.04 x 104 s. What is the
speed at which the satellite travels

A satellite is in a circular orbit about the earth
(ME = 5.98 x 1024 kg). The period of
the satellite is 2.24 x 104 s. What is the speed at
which the satellite travels?

Earth has a mass of 5.97 * 10^24 kg and a radius of 6.38 *10^6
m. Assume it is a uniform solid sphere. The distance of Earth from
the Sun is 1.50 * 10^11 m. (Assume Earth completes a single
rotation in 24.0 hours and orbits the Sun once every 365 Earth
days.)
(a) Calculate the angular momentum of Earth in its orbit around
the Sun.
(b) Calculate the angular momentum of Earth on its axis.
Please show your work.

A satellite is in a circular orbit around the Earth at an
altitude of 3.32 106 m. (a) Find the period of the orbit. (Hint:
Modify Kepler's third law so it is suitable for objects orbiting
the Earth rather than the Sun. The radius of the Earth is 6.38 106
m, and the mass of the Earth is 5.98 1024 kg.) h (b) Find the speed
of the satellite. km/s (c) Find the acceleration of the satellite.
m/s2 toward the...

1. A satellite is in a circular orbit about the earth (ME = 5.98
x 1024 kg). The period of the satellite is 2.35 x 104 s. What is
the speed at which the satellite travels?
2. Two satellites are in circular orbits around the earth. The
orbit for satellite A is at a height of 545 km above the earth’s
surface, while that for satellite B is at a height of 787 km. Find
the orbital speed for (a)...

A satellite is in a circular orbit around the Earth at an
altitude of 3.84 106 m.
(a) Find the period of the orbit. (Hint: Modify
Kepler's third law so it is suitable for objects orbiting the Earth
rather than the Sun. The radius of the Earth is
6.38 106 m, and the mass of the Earth is
5.98 1024 kg.)
h
(b) Find the speed of the satellite.
km/s
(c) Find the acceleration of the satellite.
m/s2 toward the center of the...

A satellite is in a circular orbit around the Earth at an
altitude of 1.66 106 m. (a) Find the period of the orbit (in hrs).
(Hint: Modify Kepler's third law: T2 = (4π2/GMS)r3 so it is
suitable for objects orbiting the Earth rather than the Sun. The
radius of the Earth is 6.38 106 m, and the mass of the Earth is
5.98 1024 kg.) (b) Find the speed of the satellite (in km/s). (c)
Find the acceleration of...

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