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The density of water that is at 0

The density of water that is at 0

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Answer #1

Given,

Intial volume of water = V(intial) = 3.4 m3

Bulk Modulus = B = 2.20 x 109Pascal

When the water is frozen, it normally occupies a volume which is 1.0900 V(intial)

V(final) = 1.0900 (3.4)m3

The original volume Vo of ice will be Vo = 1.0900 (3.4)m3 and final volume is V(f) = V(intial water) = 3.4 m3

V = V(f) - Vo = [1.0900 (3.4) - 3.4] = -3.4 (0.0900) m3

From the defination of bulk modulus we know that,

B = - [P / V / V(intial) ]

from this we get

P = - B ( V / V intial) = -2.20 x 109 Pascal [  -(3.4) (0.0900) m3 / (1.0900) (3.4)m3 ]

P =  -2.20 x 109 (0.0825) = 1.81 x 108 pacal = 181 MPascal

Hence P= 1.81 x 108 pacal = 181 MPascal

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